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Last updated 1 year ago

A math block that should render with KaTeX:

A math block that should be rendered with MathJax:

A math inline with KaTex: and one with MathJax

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Long inline math

1(Ο•5βˆ’Ο•)e25Ο€=1+eβˆ’2Ο€1+eβˆ’4Ο€1+eβˆ’6Ο€1+eβˆ’8Ο€1+β‹―1(Ο•5βˆ’Ο•)e25Ο€=1+eβˆ’2Ο€1+eβˆ’4Ο€1+eβˆ’6Ο€1+eβˆ’8Ο€1+β‹―1(Ο•5βˆ’Ο•)e25Ο€=1+eβˆ’2Ο€1+eβˆ’4Ο€1+eβˆ’6Ο€1+eβˆ’8Ο€1+β‹―1(Ο•5βˆ’Ο•)e25Ο€=1+eβˆ’2Ο€1+eβˆ’4Ο€1+eβˆ’6Ο€1+eβˆ’8Ο€1+β‹―1(Ο•5βˆ’Ο•)e25Ο€=1+eβˆ’2Ο€1+eβˆ’4Ο€1+eβˆ’6Ο€1+eβˆ’8Ο€1+β‹―1(Ο•5βˆ’Ο•)e25Ο€=1+eβˆ’2Ο€1+eβˆ’4Ο€1+eβˆ’6Ο€1+eβˆ’8Ο€1+β‹―\displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } } \displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } } \displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } } \displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } } \displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } } \displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } }(Ο•5β€‹β€‹βˆ’Ο•)e52​π1​=1+1+1+1+1+β‹―eβˆ’8π​eβˆ’6π​eβˆ’4π​eβˆ’2π​(Ο•5β€‹β€‹βˆ’Ο•)e52​π1​=1+1+1+1+1+β‹―eβˆ’8π​eβˆ’6π​eβˆ’4π​eβˆ’2π​(Ο•5β€‹β€‹βˆ’Ο•)e52​π1​=1+1+1+1+1+β‹―eβˆ’8π​eβˆ’6π​eβˆ’4π​eβˆ’2π​(Ο•5β€‹β€‹βˆ’Ο•)e52​π1​=1+1+1+1+1+β‹―eβˆ’8π​eβˆ’6π​eβˆ’4π​eβˆ’2π​(Ο•5β€‹β€‹βˆ’Ο•)e52​π1​=1+1+1+1+1+β‹―eβˆ’8π​eβˆ’6π​eβˆ’4π​eβˆ’2π​(Ο•5β€‹β€‹βˆ’Ο•)e52​π1​=1+1+1+1+1+β‹―eβˆ’8π​eβˆ’6π​eβˆ’4π​eβˆ’2π​
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f(x)=xβˆ—e2piiΞΎxf(x) = x * e^{2 pi i \xi x}f(x)=xβˆ—e2piiΞΎx
Οƒ_{i,BTC} =min($9600,\text{ } $2500)
f(x)=xβˆ—e2piiΞΎxf(x) = x * e^{2 pi i \xi x}f(x)=xβˆ—e2piiΞΎx
Οƒ_{i,BTC} =min($9600,\text{ } $2500)
\text{Hourly Funding Payment} = \text{Position Notional Value} \times \text{Funding Rate}\
1(Ο•5βˆ’Ο•)e25Ο€=1+eβˆ’2Ο€1+eβˆ’4Ο€1+eβˆ’6Ο€1+eβˆ’8Ο€1+β‹―\displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } }(Ο•5β€‹β€‹βˆ’Ο•)e52​π1​=1+1+1+1+1+β‹―eβˆ’8π​eβˆ’6π​eβˆ’4π​eβˆ’2π​